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15x-x^2=49
We move all terms to the left:
15x-x^2-(49)=0
We add all the numbers together, and all the variables
-1x^2+15x-49=0
a = -1; b = 15; c = -49;
Δ = b2-4ac
Δ = 152-4·(-1)·(-49)
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{29}}{2*-1}=\frac{-15-\sqrt{29}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{29}}{2*-1}=\frac{-15+\sqrt{29}}{-2} $
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